Optimal. Leaf size=218 \[ \frac{2 b^2 x^{7/2} \sqrt{a^2+2 a b x+b^2 x^2} (3 a B+A b)}{7 (a+b x)}+\frac{6 a b x^{5/2} \sqrt{a^2+2 a b x+b^2 x^2} (a B+A b)}{5 (a+b x)}+\frac{2 a^2 x^{3/2} \sqrt{a^2+2 a b x+b^2 x^2} (a B+3 A b)}{3 (a+b x)}+\frac{2 b^3 B x^{9/2} \sqrt{a^2+2 a b x+b^2 x^2}}{9 (a+b x)}+\frac{2 a^3 A \sqrt{x} \sqrt{a^2+2 a b x+b^2 x^2}}{a+b x} \]
[Out]
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Rubi [A] time = 0.243373, antiderivative size = 218, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.065 \[ \frac{2 b^2 x^{7/2} \sqrt{a^2+2 a b x+b^2 x^2} (3 a B+A b)}{7 (a+b x)}+\frac{6 a b x^{5/2} \sqrt{a^2+2 a b x+b^2 x^2} (a B+A b)}{5 (a+b x)}+\frac{2 a^2 x^{3/2} \sqrt{a^2+2 a b x+b^2 x^2} (a B+3 A b)}{3 (a+b x)}+\frac{2 b^3 B x^{9/2} \sqrt{a^2+2 a b x+b^2 x^2}}{9 (a+b x)}+\frac{2 a^3 A \sqrt{x} \sqrt{a^2+2 a b x+b^2 x^2}}{a+b x} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/Sqrt[x],x]
[Out]
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Rubi in Sympy [A] time = 24.9063, size = 216, normalized size = 0.99 \[ \frac{B \sqrt{x} \left (2 a + 2 b x\right ) \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{9 b} + \frac{32 a^{3} \sqrt{x} \left (9 A b - B a\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{315 b \left (a + b x\right )} + \frac{16 a^{2} \sqrt{x} \left (9 A b - B a\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{315 b} + \frac{4 a \sqrt{x} \left (3 a + 3 b x\right ) \left (9 A b - B a\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{315 b} + \frac{2 \sqrt{x} \left (9 A b - B a\right ) \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{63 b} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**(3/2)/x**(1/2),x)
[Out]
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Mathematica [A] time = 0.0819355, size = 88, normalized size = 0.4 \[ \frac{2 \sqrt{x} \sqrt{(a+b x)^2} \left (105 a^3 (3 A+B x)+63 a^2 b x (5 A+3 B x)+27 a b^2 x^2 (7 A+5 B x)+5 b^3 x^3 (9 A+7 B x)\right )}{315 (a+b x)} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/Sqrt[x],x]
[Out]
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Maple [A] time = 0.01, size = 92, normalized size = 0.4 \[{\frac{70\,B{x}^{4}{b}^{3}+90\,A{b}^{3}{x}^{3}+270\,B{x}^{3}a{b}^{2}+378\,A{x}^{2}a{b}^{2}+378\,B{x}^{2}{a}^{2}b+630\,A{a}^{2}bx+210\,{a}^{3}Bx+630\,A{a}^{3}}{315\, \left ( bx+a \right ) ^{3}}\sqrt{x} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/x^(1/2),x)
[Out]
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Maxima [A] time = 0.702544, size = 184, normalized size = 0.84 \[ \frac{2}{105} \,{\left (3 \,{\left (5 \, b^{3} x^{2} + 7 \, a b^{2} x\right )} x^{\frac{3}{2}} + 14 \,{\left (3 \, a b^{2} x^{2} + 5 \, a^{2} b x\right )} \sqrt{x} + \frac{35 \,{\left (a^{2} b x^{2} + 3 \, a^{3} x\right )}}{\sqrt{x}}\right )} A + \frac{2}{315} \,{\left (5 \,{\left (7 \, b^{3} x^{2} + 9 \, a b^{2} x\right )} x^{\frac{5}{2}} + 18 \,{\left (5 \, a b^{2} x^{2} + 7 \, a^{2} b x\right )} x^{\frac{3}{2}} + 21 \,{\left (3 \, a^{2} b x^{2} + 5 \, a^{3} x\right )} \sqrt{x}\right )} B \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)/sqrt(x),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.307745, size = 99, normalized size = 0.45 \[ \frac{2}{315} \,{\left (35 \, B b^{3} x^{4} + 315 \, A a^{3} + 45 \,{\left (3 \, B a b^{2} + A b^{3}\right )} x^{3} + 189 \,{\left (B a^{2} b + A a b^{2}\right )} x^{2} + 105 \,{\left (B a^{3} + 3 \, A a^{2} b\right )} x\right )} \sqrt{x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)/sqrt(x),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\left (A + B x\right ) \left (\left (a + b x\right )^{2}\right )^{\frac{3}{2}}}{\sqrt{x}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**(3/2)/x**(1/2),x)
[Out]
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GIAC/XCAS [A] time = 0.272508, size = 169, normalized size = 0.78 \[ \frac{2}{9} \, B b^{3} x^{\frac{9}{2}}{\rm sign}\left (b x + a\right ) + \frac{6}{7} \, B a b^{2} x^{\frac{7}{2}}{\rm sign}\left (b x + a\right ) + \frac{2}{7} \, A b^{3} x^{\frac{7}{2}}{\rm sign}\left (b x + a\right ) + \frac{6}{5} \, B a^{2} b x^{\frac{5}{2}}{\rm sign}\left (b x + a\right ) + \frac{6}{5} \, A a b^{2} x^{\frac{5}{2}}{\rm sign}\left (b x + a\right ) + \frac{2}{3} \, B a^{3} x^{\frac{3}{2}}{\rm sign}\left (b x + a\right ) + 2 \, A a^{2} b x^{\frac{3}{2}}{\rm sign}\left (b x + a\right ) + 2 \, A a^{3} \sqrt{x}{\rm sign}\left (b x + a\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)/sqrt(x),x, algorithm="giac")
[Out]